Example B: Different Coat Colours
Sire is a Rosy Brown (brown rarity 7) and Dam is Antique White (greyscale rarity 9).
These two racehorses are not the same colours, nor in the same Colour Group.
To begin, we apply the first part of the logic:
  • 40% chance: { [Dam Coat Colour Rarity x 0.35] + [Sire Coat Colour Rarity x 0.65] } and randomly select any Coat Colour, from that Rarity Tier (figures are always rounded up)
  • 30% chance: same Colour Box as Sire (Father)
  • 20% chance: same Colour Box as Dam (Mother)
  • 6.5% chance: same Coat Colour as Sire (Father)
  • 3.5% chance: same Coat Colour as Dam (Mother)
Now let us assume that randomly, the first part of the logic is selected being:
= { [Dam Breeding Rarity x 0.35) + (Sire Breeding Rarity x .65] }
= { [9 x 0.35] + [7 x .65)] } = x (round up)
= [3.15 + 4.55]
= 7.70
= 8 (round up)
Therefore, there is a 40% chance that the offsprings\ Coat Colour will be randomly selected from the Rarity Tier titled “Rare”. For this example, we will assume the colour Burlywood (rarity is 8) is selected. Therefore, we will now apply the rarity check formula being:
Breeding Rarity (br) = [r³] / 1000
= (8 x 8 x 8) / 1000 = 0.512 = 51.2%
Therefore, there is a 51.2% chance that the offspring will be given a Burlywood colour and a 48.8% chance that it will drop to the lower rarity level of the same colour pyramid and a new colour is selected at random.
Last modified 5mo ago
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