Example B: Different Coat Colours
Last updated
Last updated
Sire is a Rosy Brown (brown rarity 7) and Dam is Antique White (greyscale rarity 9).
These two racehorses are not the same colours, nor in the same Colour Group.
To begin, we apply the first part of the logic:
40% influence: { [Dam Coat Colour Rarity x 0.35] + [Sire Coat Colour Rarity x 0.65] } and select any Coat Colour, from that Rarity Tier (figures are always rounded up)
30% influence: same Colour Box as Sire (Father)
20% influence: same Colour Box as Dam (Mother)
6.5% influence: same Coat Colour as Sire (Father)
3.5% influence: same Coat Colour as Dam (Mother)
Now let us assume that the first part of the logic is selected being:
= { [Dam Breeding Rarity x 0.35) + (Sire Breeding Rarity x .65] }
= { [9 x 0.35] + [7 x .65)] } = x (round up)
= [3.15 + 4.55]
= 7.70
= 8 (round up)
Therefore, 40% of the time, the offspring's Coat Colour will be determined from the Rarity Tier titled “Rare”.
Breeding Rarity (br) = [r³] / 1000
= (8 x 8 x 8) / 1000 = 0.512 = 51.2%
Therefore, 51.2% of the time, the offspring will be given a Burlywood colour and 48.8% of the time, it will drop to the lower rarity level of the same colour pyramid and a new colour is determined.
